Math Component
Step 1: Identify the equation. Use the projectile motion formula:
h= -16t2+v0t+h0. Now plug in the initial velocity of 192feet per second for v0t and 32 feet as the h0.
It should look like this: h= -16t2+ 192t+32. We are looking for the cannon ball’s highest point(vertex) and how long the cannon ball is in the air (use the quadratic formula).
Step 2: Identify the variables and then find the vertex by using
a= -16
b= 192
c= 32 Now plug and chug.
Step 3: Now plug in 6 as “t” to find the highest point the ball will go.
h= -16(6) + 192(6) + 32. Your answer should be: 608 feet as the cannon ball’s maximum height.
Step 4: To find the cannon ball’s time in the air, use the quadratic formula and plug in “a”, “b” and “c” from step 2.
x=
x=
x= -192 ± √ 38,912/-32
Step 5: Your answer should be positive since time cannot go backwards. So x= 12 is the correct time.
I got 12, too. (: Although you might want to add .16 to the end of 12, because Mrs. Tyrpak told me she wanted it rounded to the nearest hundredths place.
ReplyDeleteya i must agree on what amanda said you must make a more specific number
ReplyDeletei believe that you should do something with the "x=" rather than just having it "floating" there.Space between 192 and feet under the first step.But other wise great job.
ReplyDeleteAlright I did thanks!
ReplyDelete